fix(post): another typo
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@ -166,7 +166,7 @@
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because \(log_2(x)\) is not available in python.
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</li>
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<li>
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It's certainly possible that \(max(nums, k)=0\). To avoid
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It's certainly possible that \(max\{nums, k\}=0\). To avoid
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the invalid calculation \(log(0)\), take the larger of \(1\) and
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this calculation. The number of digits will then (correctly) be
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\(1\) in this special case.
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