121 lines
2.3 KiB
C++
121 lines
2.3 KiB
C++
#include <bits/stdc++.h> // {{{
|
|
|
|
// https://codeforces.com/blog/entry/96344
|
|
|
|
#pragma GCC optimize("O2,unroll-loops")
|
|
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
|
|
|
|
using namespace std;
|
|
|
|
template <typename T>
|
|
[[nodiscard]] static T MIN() {
|
|
return std::numeric_limits<T>::min();
|
|
}
|
|
|
|
template <typename T>
|
|
[[nodiscard]] static T MAX() {
|
|
return std::numeric_limits<T>::max();
|
|
}
|
|
|
|
template <typename T>
|
|
[[nodiscard]] static T sc(auto&& x) {
|
|
return static_cast<T>(x);
|
|
}
|
|
|
|
template <typename T>
|
|
[[nodiscard]] static T sz(auto&& x) {
|
|
return static_cast<T>(x.size());
|
|
}
|
|
|
|
#define prln(...) std::println(__VA_ARGS__)
|
|
#define pr(...) std::print(__VA_ARGS__)
|
|
|
|
#ifdef LOCAL
|
|
#define dbgln(...) std::println(__VA_ARGS__)
|
|
#define dbg(...) std::print(__VA_ARGS__)
|
|
#endif
|
|
|
|
inline static void NO() {
|
|
prln("NO");
|
|
}
|
|
|
|
inline static void YES() {
|
|
prln("YES");
|
|
}
|
|
|
|
using ll = long long;
|
|
using ld = long double;
|
|
template <typename T>
|
|
using ve = std::vector<T>;
|
|
template <typename T, size_t N>
|
|
using ar = std::array<T, N>;
|
|
template <typename T1, typename T2>
|
|
using pa = std::pair<T1, T2>;
|
|
template <typename... Ts>
|
|
using tu = std::tuple<Ts...>;
|
|
template <typename... Ts>
|
|
using dq = std::deque<Ts...>;
|
|
template <typename... Ts>
|
|
using qu = std::queue<Ts...>;
|
|
template <typename... Ts>
|
|
using pq = std::priority_queue<Ts...>;
|
|
template <typename... Ts>
|
|
using st = std::stack<Ts...>;
|
|
auto lb = [](auto... args) {
|
|
return std::lower_bound(args...);
|
|
};
|
|
auto ub = [](auto... args) {
|
|
return std::upper_bound(args...);
|
|
};
|
|
|
|
#define ff first
|
|
#define ss second
|
|
#define eb emplace_back
|
|
#define pb push_back
|
|
#define all(x) (x).begin(), (x).end()
|
|
#define rall(x) (x).rbegin(), (x).rend()
|
|
// }}}
|
|
|
|
void solve() {
|
|
int n, m;
|
|
cin >> n >> m;
|
|
ve<int> out(n + 1, 0);
|
|
ve<ve<int>> G(n + 1);
|
|
while (m--) {
|
|
int u, v;
|
|
cin >> u >> v;
|
|
++out[u];
|
|
++out[v];
|
|
G[u].eb(v);
|
|
G[v].eb(u);
|
|
}
|
|
|
|
for (int u = 1; u <= n; ++u) {
|
|
if (out[u] == 1) {
|
|
int v = G[u][0];
|
|
int y = out[v] - 1;
|
|
for (auto w : G[v]) {
|
|
if (out[w] > 1) {
|
|
int x = out[w];
|
|
prln("{} {}", x, y);
|
|
return;
|
|
}
|
|
}
|
|
}
|
|
}
|
|
}
|
|
|
|
int main() { // {{{
|
|
cin.tie(nullptr)->sync_with_stdio(false);
|
|
cin.exceptions(cin.failbit);
|
|
|
|
int t = 1;
|
|
cin >> t;
|
|
|
|
while (t--) {
|
|
solve();
|
|
}
|
|
|
|
return 0;
|
|
}
|
|
// }}}
|