#include // {{{ // https://codeforces.com/blog/entry/96344 #pragma GCC optimize("O2,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") using namespace std; template [[nodiscard]] static T MIN() { return std::numeric_limits::min(); } template [[nodiscard]] static T MAX() { return std::numeric_limits::max(); } template [[nodiscard]] static T sc(auto&& x) { return static_cast(x); } template [[nodiscard]] static T sz(auto&& x) { return static_cast(x.size()); } #define prln(...) std::println(__VA_ARGS__) #define pr(...) std::print(__VA_ARGS__) #ifdef LOCAL #define dbgln(...) std::println(__VA_ARGS__) #define dbg(...) std::print(__VA_ARGS__) #endif inline static void NO() { prln("NO"); } inline static void YES() { prln("YES"); } using ll = long long; using ld = long double; template using ve = std::vector; template using ar = std::array; template using pa = std::pair; template using tu = std::tuple; template using dq = std::deque; template using qu = std::queue; template using pq = std::priority_queue; template using st = std::stack; auto lb = [](auto... args) { return std::lower_bound(args...); }; auto ub = [](auto... args) { return std::upper_bound(args...); }; #define ff first #define ss second #define eb emplace_back #define pb push_back #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() // }}} string reverseIntervals(string s, vector>& intervals) { int n = s.length(); vector flip(n + 1, 0); for (auto& interval : intervals) { int start = interval.ff, end = interval.ss; if (start >= 0 && end < n && start <= end) { flip[start]++; flip[end + 1]--; } } int current = 0; for (int i = 0; i < n; ++i) { current += flip[i]; if (current % 2 == 1) { int j = n - 1 - i; if (i < j) { swap(s[i], s[j]); } } } return s; } void solve() { int k, n; cin >> n >> k; string s; cin >> s; ve L(k), R(k); for (auto& e : L) cin >> e; for (auto& e : R) cin >> e; int q; cin >> q; int x; ve> intervals; while (q--) { cin >> x; int l = 0, r = k - 1; while (l <= r) { int m = l + (r - l) / 2; if (L[m] <= x) { l = m + 1; } else { r = m - 1; } } int i = r; int left = min(x, R[i] + L[i] - x), right = max(x, R[i] + L[i] - x); prln("{} {}", left - 1, right - 1); intervals.eb(left - 1, right - 1); } string ans = reverseIntervals(s, intervals); prln("{}", ans); } int main() { // {{{ cin.tie(nullptr)->sync_with_stdio(false); cin.exceptions(cin.failbit); int t = 1; cin >> t; while (t--) { solve(); } return 0; } // }}}