#include // {{{ #include #ifdef __cpp_lib_ranges_enumerate #include namespace rv = std::views; namespace rs = std::ranges; #endif // https://codeforces.com/blog/entry/96344 #pragma GCC optimize("O2,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") using namespace std; using i32 = int32_t; using u32 = uint32_t; using i64 = int64_t; using u64 = uint64_t; using f64 = double; using f128 = long double; #if __cplusplus >= 202002L template constexpr T MIN = std::numeric_limits::min(); template constexpr T MAX = std::numeric_limits::max(); template [[nodiscard]] static T sc(auto&& x) { return static_cast(x); } template [[nodiscard]] static T sz(auto&& x) { return static_cast(x.size()); } #endif static void NO() { std::cout << "NO\n"; } static void YES() { std::cout << "YES\n"; } template using vec = std::vector; #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define ff first #define ss second #ifdef LOCAL #define db(...) std::print(__VA_ARGS__) #define dbln(...) std::println(__VA_ARGS__) #else #define db(...) #define dbln(...) #endif // }}} void solve() { u32 n, m; cin >> n >> m; // NOTE: missed, think big picture // consider pos n - can either jump one and pay a[n], or skip and pay b[n] (static, must pay b[n]) // so - just do the best, lol // then, brute-force consider any choices from 1-m vec a(n), b(n); for (auto& e : a) cin >> e; for (auto& e : b) cin >> e; i32 pos = n; u64 acc = 0; for (i32 i = n - 1; i >= m; --i) { acc += min(a[i], b[i]); } u64 ans = MAX; u64 prefix = 0; for (i32 i = m - 1; i >= 0; --i) { ans = min(ans, acc + prefix + a[i]); prefix += min(a[i], b[i]); } println("{}", ans); } int main() { // {{{ std::cin.exceptions(std::cin.failbit); #ifdef LOCAL std::cerr.rdbuf(std::cout.rdbuf()); std::cout.setf(std::ios::unitbuf); std::cerr.setf(std::ios::unitbuf); #else std::cin.tie(nullptr)->sync_with_stdio(false); #endif u32 tc = 1; std::cin >> tc; for (u32 t = 0; t < tc; ++t) { solve(); } return 0; } // }}}